| A |
| |
9
+ 3 – 2 – 1= |
| |
©1996,
Kaidy |
|
| Rules of Operation: |
|
a.
|
Solve inside all parentheses first --rules b and c
apply internally; |
b. |
Multiply and divide from left to right; then |
| c. |
Add and subtract from left to right. |
|
| B |
| |
9
+ 3 x 2 + 1 = |
| |
©1996, Kaidy |
|
| C |
| |
(9–3)
÷ (2+1)= |
| |
©1996, Kaidy |
|
| D |
| |
9
+ 3 ÷ (2+1)= |
| |
©1996, Kaidy |
|
| E |
| |
(9+3)
÷ 2 + 1 = |
| |
©1996, Kaidy |
|
| F |
| |
(9–3)
÷ (2–1) = |
| |
©1996, Kaidy |
|
| G |
| |
9
– 3 x 2 x 1 = |
| |
©1996, Kaidy |
|
| H |
| |
9
÷ (3–2) – 1 = |
| |
©1996, Kaidy |
|
| I |
| |
9
÷ 3 – 2 ÷ 1 = |
| |
©1996, Kaidy |
|
| J |
| |
9
+ (3+2) x 1 = |
| |
©1996, Kaidy |
|
| K |
| |
(9+3)
÷ 2 – 1 = |
| |
©1996, Kaidy |
|
| L |
| |
(9–3)
x 2 + 1 = |
| |
©1996, Kaidy |
|
| M |
| |
9
+ 3 x 2 ÷ 1 = |
| |
©1996, Kaidy |
|
| N |
| |
9 – (3+2) x 1 = |
| |
©1996, Kaidy |
|
| O |
| |
9
+ 3 ÷ (2–1) = |
| |
©1996, Kaidy |
|
| P |
| |
(9–3)
x 2 – 1 = |
| |
©1996, Kaidy |
|
